5.3 The Fundamental Theorem of Calculus/9: Difference between revisions
No edit summary |
No edit summary |
||
| Line 9: | Line 9: | ||
</math> | </math> | ||
<math> | <math> | ||
\text{Therefore, } g'(y) = y^{2}\sin{(y)} | \text{Therefore, } g'(y) = y^{2}\sin{(y)} | ||
</math> | </math> | ||
Revision as of 19:56, 6 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle g(y)= \int_{2}^{y}t^2\sin{(t)}dt}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \frac{d}{dy}\left[g(y)\right] = \frac{d}{dy}\left[\int_{2}^{y}t^2\sin{(t)}dt\right] = 1\cdot((y)^{2}\sin{y})-0\cdot((0)^{2}\sin{(2)}) = y^{2}\sin{(y)} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \text{Therefore, } g'(y) = y^{2}\sin{(y)} }