5.5 The Substitution Rule/1: Difference between revisions

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& du=-dx\\ [2ex]
& du=-dx\\ [2ex]


& \int{e^{-x}} dx \\ [2ex]  
& \int{e^{-x}} dx \\ [2ex] &=
 


&= -\int{e^{u}} du \\ [2ex]   
&= -\int{e^{u}} du \\ [2ex]   

Revision as of 19:46, 1 September 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&\int {e^{-x}}dx,u=-x\\[2ex]&u=-x\\[2ex]&du=-dx\\[2ex]&\int {e^{-x}}dx\\[2ex]&=&=-\int {e^{u}}du\\[2ex]&=-e^{u}du\\[2ex]&=-e^{-x}+C\\[2ex]\end{aligned}}}