5.5 The Substitution Rule/1: Difference between revisions

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& \int{e^{-x}} dx ,u=-x \\[2ex]
& \int{e^{-x}} dx ,u=-x \\[2ex]


u=-x \\ [2ex]
& u=-x \\ [2ex]


du=-1dx \\ [2ex]
& du=-1dx=\\ [2ex]


& \int{e^{-x}} dx \\[2ex]
& \int{e^{-x}} dx \\[2ex]

Revision as of 19:28, 1 September 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \int{e^{-x}} dx ,u=-x \\[2ex] & u=-x \\ [2ex] & du=-1dx=\\ [2ex] & \int{e^{-x}} dx \\[2ex] & -\int{e^{u}} du \\ [2ex] & -e^{u} du \\ [2ex] & -e^{-x}+C \end{align} }