5.5 The Substitution Rule/1: Difference between revisions

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& \int{e^-x} dx \\[2ex]
& \int{e^-x} dx \\[2ex]
& \-int{e^u} du \\[2ex]
& -\e^u du\\[2ex]
&= -\e^-x+C


\end{align}
\end{align}
</math>
</math>

Revision as of 19:23, 1 September 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&\int {e^{-}x}dx\\[2ex],u=-x&\int {e^{-}x}dx\\[2ex]\end{aligned}}}