5.3 The Fundamental Theorem of Calculus/33: Difference between revisions
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<math>\frac{d}{dx}\left[h(x)\right]=\frac{d}{dx}\left[int_{2}^{1/x}\arctan(t)dt\right] | <math>\frac{d}{dx}\left[h(x)\right]=\frac{d}{dx}\left[int_{2}^{1/x}\arctan(t)dt\right] | ||
\frac{-1}{x^2}\left(\arctan(\frac{1}{x}\right)-0</math> | <math>\frac{-1}{x^2}\left(\arctan(\frac{1}{x}\right)-0</math> | ||
Revision as of 19:50, 25 August 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle h(x)=\int_{2}^{1/x}\arctan(t)dt}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \frac{d}{dx}\left[h(x)\right]=\frac{d}{dx}\left[int_{2}^{1/x}\arctan(t)dt\right] <math>\frac{-1}{x^2}\left(\arctan(\frac{1}{x}\right)-0}