5.3 The Fundamental Theorem of Calculus/23: Difference between revisions

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&\int_{0}^{1}x^\cfrac{4}{5}dx \\[2ex]
&\int_{0}^{1}x^\cfrac{4}{5}dx \\[2ex]


&= \cfrac{5}\sqrt[5]{x^4}
&= \cfrac{5}*\sqrt[5]{x^4}




\end{align}
\end{align}
</math>
</math>

Revision as of 19:00, 25 August 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&\int _{0}^{1}x^{\cfrac {4}{5}}dx\\[2ex]&={\cfrac {5}{*}}{\sqrt[{5}]{x^{4}}}\end{aligned}}}