7.1 Integration By Parts/28: Difference between revisions
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\begin{align} | \begin{align} | ||
\int_{1}^{2}\frac{\ln{x}^2}{x^3} = -\frac{\ln{x}}{2x^2} - \int-\frac{1}{2x^3} | & \int_{1}^{2}\frac{\ln{x}^2}{x^3} = -\frac{\ln{x}}{2x^2} - \int-\frac{1}{2x^3} \\[2ex] | ||
& = -\frac{\ln{x}}{2x^2} - \frac{1}{2}\int\frac{1}{x^3} \\[2ex] | & = -\frac{\ln{x}}{2x^2} - \frac{1}{2}\int\frac{1}{x^3} \\[2ex] | ||
Revision as of 21:58, 16 December 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{2}\frac{\ln{x}^2}{x^3} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle u = \ln{x} \qquad dv = \frac{1}{x^3} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle du = \frac{1}{x} \qquad v = -\frac{1}{2x^2} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \int_{1}^{2}\frac{\ln{x}^2}{x^3} = -\frac{\ln{x}}{2x^2} - \int-\frac{1}{2x^3} \\[2ex] & = -\frac{\ln{x}}{2x^2} - \frac{1}{2}\int\frac{1}{x^3} \\[2ex] \end{align} }