7.1 Integration By Parts/53: Difference between revisions

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\begin{align}
\begin{align}
u &= x \quad dv= e^{-0.4x} dx \\[2ex]
u &= x \quad dv= e^{-0.4x} dx \\[2ex]
du &= dx        \qquad v= -e^{-x} \\[2ex]
du &= dx        \qquad v= \frac{5}{2}e^{-0.4x} \\[2ex]


\end{align}
\end{align}
</math>
</math>

Revision as of 12:40, 13 December 2022