6.5 Average Value of a Function/17

1. Use the Average Value from a to b:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle f_{\text{avg}} = \frac{1}{b-a}\int_{a}^{b}f(x)\,dx }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \frac{1}{12}\int_{0}^{12} 50 + 14\sin(\frac{\pi}{12}t)\,dt =\frac{1}{12}[50t-\frac{168}{\pi}\cos(\frac{\pi}{12}t)]\bigg|_{12}^{0} }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} u &= \frac{\pi}{12}t \quad \quad \quad \quad \quad \int14\sin(u)\frac{12}{\pi}\,du \\ \quad dt\cdot\frac{du}{dt} &= dt \quad \quad \quad \quad 14\cdot\frac{12}{\pi}\int\sin(u)\,du \\ \frac{12}{\pi}du &= dt \quad \quad \quad \quad -\frac{168}{\pi}\cos(u) =-\frac{168}{\pi}\cos(\frac{\pi}{12}t) \\ \end{align} }