7.1 Integration By Parts/51b: Difference between revisions

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\begin{align}
\begin{align}


\int\ln(x)^3dx &= x\ln(x)^3 -\underbrace[3]{3\int\ln(x)^2dx}_{  
\int\ln(x)^3dx &= x\ln(x)^3 -\underbrace[10][20]{3\int\ln(x)^2dx}_{  
\begin{aligned}
\begin{aligned}
u & = \ln^{2}{(x)}  & dv &= dx \\[0.6ex]
u & = \ln^{2}{(x)}  & dv &= dx \\[0.6ex]

Revision as of 18:21, 29 November 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \text{Use } \int(\ln{(x)}^{n} = x(\ln{x})^n - n\int(\ln{x})^{n-1}dx }


Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\int \ln(x)^{3}dx&=x\ln(x)^{3}-\underbrace {[} 10][20]{3\int \ln(x)^{2}dx}_{\begin{aligned}u&=\ln ^{2}{(x)}&dv&=dx\\[0.6ex]du&={\tfrac {2\ln {(x)}}{x}}dx&v&=x\end{aligned}}\\[2ex]&=x\ln ^{3}(x)-3\left[\ln ^{2}{(x)}\cdot x-2\int \ln {(x)}dx\right]\\[1ex]&=x\ln ^{3}(x)-3x\ln ^{2}{(x)}+\underbrace {6\int \ln {(x)}dx} _{\begin{aligned}u&=\ln {(x)}&dv&=dx\\[0.6ex]du&={\tfrac {1}{x}}dx&v&=x\end{aligned}}\\[2ex]&=x\ln ^{3}(x)-3x\ln ^{2}{(x)}+6\left[\ln {(x)}\cdot x-\int dx\right]\\[1ex]&=x\ln ^{3}(x)-3x\ln ^{2}{(x)}+6x\ln {(x)}-6x+C\end{aligned}}}