7.1 Integration By Parts/49: Difference between revisions
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<math> | <math> | ||
\begin{align} | \begin{align} | ||
&u = \tan^{n-2}x \ | &u = \tan^{n-2}x \quad dv= \sec^{2}(x)dx \\[2ex] | ||
&du = (n-2)\tan^{n-3}x \cdot \sec(x)\tan(x)dx \quad v=x \\[2ex] | &du = (n-2)\tan^{n-3}x \cdot \sec(x)\tan(x)dx \quad v= \tan(x) \\[2ex] | ||
\end{align} | \end{align} | ||
Revision as of 18:17, 29 November 2022
Prove Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{}^{} \left(\tan^{n}(x)\right)dx =\frac{\tan^{n-1}x}{n-1} - \int_{}^{} \left(\tan^{n-2}x\right)dx }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{}^{} \left(\tan^{n}(x)\right)dx = \int_{}^{} \left((\tan^{2}x)(\tan^{n-2}x)\right)dx = \int_{}^{} (\sec^{2}(x)-1)\tan^{n-2}(x) dx = \int_{}^{} (\sec^{2}x)(\tan^{n-2}x)-\tan^{n-2}xdx = \int_{}^{} (\sec^{2}x)(\tan^{n-2}x) -\int_{}^{}\tan^{n-2}xdx }
Solving for Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{}^{} (\sec^{2}x)(\tan^{n-2}x) }
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&u=\tan ^{n-2}x\quad dv=\sec ^{2}(x)dx\\[2ex]&du=(n-2)\tan ^{n-3}x\cdot \sec(x)\tan(x)dx\quad v=\tan(x)\\[2ex]\end{aligned}}}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \int_{}^{} \left(\ln(x)^{n}\right)dx &= x \ln(x)^{n} - \int_{}^{} \left((x \frac{n \ln(x)^{n-1}}{x}) \right)dx \\[2ex] &= x \ln(x)^{n} - \int_{}^{} \left(n \ln(x)^{n-1} \right)dx \\[2ex] &= x \ln(x)^{n} - n \int_{}^{} \left(\ln(x)^{n-1} \right)dx \\[2ex] \end{align} }