7.1 Integration By Parts/49: Difference between revisions

From Mr. V Wiki Math
Jump to navigation Jump to search
No edit summary
No edit summary
Line 19: Line 19:
<math>
<math>
\begin{align}
\begin{align}
&u = \tan^{n-2}x \qqquad dv= 1dx \\[2ex]
&u = \tan^{n-2}x \quad dv= \sec^{2}(x)dx \\[2ex]
&du = (n-2)\tan^{n-3}x \cdot \sec(x)\tan(x)dx        \quad v=x \\[2ex]
&du = (n-2)\tan^{n-3}x \cdot \sec(x)\tan(x)dx        \quad v= \tan(x) \\[2ex]


\end{align}
\end{align}

Revision as of 18:17, 29 November 2022

Prove Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{}^{} \left(\tan^{n}(x)\right)dx =\frac{\tan^{n-1}x}{n-1} - \int_{}^{} \left(\tan^{n-2}x\right)dx }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{}^{} \left(\tan^{n}(x)\right)dx = \int_{}^{} \left((\tan^{2}x)(\tan^{n-2}x)\right)dx = \int_{}^{} (\sec^{2}(x)-1)\tan^{n-2}(x) dx = \int_{}^{} (\sec^{2}x)(\tan^{n-2}x)-\tan^{n-2}xdx = \int_{}^{} (\sec^{2}x)(\tan^{n-2}x) -\int_{}^{}\tan^{n-2}xdx }

Solving for Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{}^{} (\sec^{2}x)(\tan^{n-2}x) }

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&u=\tan ^{n-2}x\quad dv=\sec ^{2}(x)dx\\[2ex]&du=(n-2)\tan ^{n-3}x\cdot \sec(x)\tan(x)dx\quad v=\tan(x)\\[2ex]\end{aligned}}}

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \int_{}^{} \left(\ln(x)^{n}\right)dx &= x \ln(x)^{n} - \int_{}^{} \left((x \frac{n \ln(x)^{n-1}}{x}) \right)dx \\[2ex] &= x \ln(x)^{n} - \int_{}^{} \left(n \ln(x)^{n-1} \right)dx \\[2ex] &= x \ln(x)^{n} - n \int_{}^{} \left(\ln(x)^{n-1} \right)dx \\[2ex] \end{align} }