7.1 Integration By Parts/51b: Difference between revisions

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\begin{aligned}
\begin{aligned}
u &= x^{2}+1 \quad dv= e^{-x}dx \\[2ex]
u &= \ln^{2}{x} \quad dv=dx \\[2ex]
du &= 2xdx       \qquad v= -e^{-x} \\[2ex]
du &= \frac{2}{x}\ln{x}dx       \qquad v=x \\[2ex]


\end{aligned}
\end{aligned}

Revision as of 17:45, 29 November 2022