7.1 Integration By Parts/11: Difference between revisions

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<math>
<math>
\begin{align}
\begin{align}
& u=1+16t^{2}  
& u=1+16t^{2} \\ [1ex]
& du=32t dt  
& du=32t dt \\ [1ex]
& \frac{1}{32}du=t dt  
& \frac{1}{32}du=t dt  
\end{align}
\end{align}
</math> <br><br>
</math>

Revision as of 05:27, 29 November 2022