7.1 Integration By Parts/11: Difference between revisions

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<math>
<math>
\begin{align}
\begin{align}
& u=1+16t^{2} \\[1ex]
& u=1+16t^{2} \\[1ex]
& du=32t dt \\[1ex]
& du=32t dt \\[1ex]

Revision as of 05:12, 29 November 2022