6.2 Volumes/19: Difference between revisions

Latest revision as of 04:34, 29 November 2022

$V=\int _{0}^{1}\pi (x^{3})^{2}=\int _{0}^{1}(\pi x^{6})dx$

$V={\Bigg |}_{0}^{1}\pi {\frac {x^{7}}{7}}={\frac {\pi }{7}}$

@@ Line 1: / Line 1: @@
-<math>V=\int_{0}^{1} \pi(x^{3})^{2}=\int_{0}^{1}(\pi x^{6})dx </math>< br> <br>
+<math>V=\int_{0}^{1} \pi(x^{3})^{2}=\int_{0}^{1}(\pi x^{6})dx </math><br><br>
 <math>
 V = \Bigg|_{0}^{1} \pi \frac{x^7}{7} = \frac{\pi}{7}