7.1 Integration By Parts/54: Difference between revisions

From Mr. V Wiki Math
Jump to navigation Jump to search
No edit summary
No edit summary
Line 12: Line 12:
&x=1 \\[1ex]
&x=1 \\[1ex]


\end{align}
</math>
When <math> x=2 </math>
<math>
5\ln(2) > 2\ln(2)
5\ln(2) > 2\ln(2)
\end{align}
</math>
</math>



Revision as of 04:27, 29 November 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}5\ln(x)&=x\ln(x)\\[1ex]&x=5\\[1ex]&x=1\\[1ex]\end{aligned}}}

When Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle 5\ln(2)>2\ln(2)}

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int _{1}^{5}\left(5\ln(x)-x\ln(x)\right)dx={\color {NavyBlue}\int _{1}^{5}\left(5\ln(x)\right)dx}-{\color {RedOrange}\int _{1}^{5}\left(x\ln(x)\right)dx}=25\ln(5)-20-\left({\frac {25}{2}}\ln(5)-6\right)={\frac {25}{2}}\ln(5)-14}

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\color {RedOrange}\int _{1}^{5}\left(x\ln(x)\right)dx}={\frac {x^{2}\ln(x)}{2}}{\bigg |}_{1}^{5}-\int _{1}^{5}\left({\frac {x^{2}}{2x}}\right)dx={\frac {x^{2}\ln(x)}{2}}{\bigg |}_{1}^{5}-{\frac {1}{2}}\int _{1}^{5}\left(x\right)dx={\frac {1\ln(1)}{2}}-{\frac {25\ln(5)}{2}}-\left({\frac {1}{2}}\right)\left({\frac {x^{2}}{2}}\right){\bigg |}_{1}^{5}=0-{\frac {25}{2}}\ln(5)-{\frac {1}{2}}\left({\frac {25-1}{2}}\right)={\frac {25}{2}}\ln(5)-6}