7.1 Integration By Parts/13: Difference between revisions

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<math>\int t\sec^2\left(2t\right) dt </math>
<math>\int t\sec^2\left(2t\right) dt </math>


<math> u = t \qquad dv = \sec^2\left(2t\right)
<math>u = t \qquad dv = \sec^2\left(2t\right)</math> <br><br>
 
<math>du = dt \qquad v = \frac{1}{2}\tan\left(2t\right)</math>
</math>

Revision as of 02:52, 29 November 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int t\sec^2\left(2t\right) dt }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle u = t \qquad dv = \sec^2\left(2t\right)}

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle du = dt \qquad v = \frac{1}{2}\tan\left(2t\right)}