6.2 Volumes/3

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${\begin{aligned}\pi \int _{1}^{2}\left[\left({\frac {1}{x}}\right)^{2}\right]dx&=\pi \int _{1}^{2}\left[\left({\frac {1}{x^{2}}}\right)\right]dx&=\pi \left[-{\frac {1}{x}}\right]\end{aligned}}$