6.5 Average Value of a Function/17: Difference between revisions

Revision as of 00:30, 29 November 2022

$\int _{0}^{12}50+14\sin({\frac {\pi }{12}}t)\,dt={\frac {1}{12}}$

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 <math>
-\int_{0}^{12} 50 + 14\sin(\frac{\pi}{12}t)\,dt =\frac[1}{12}
+\int_{0}^{12} 50 + 14\sin(\frac{\pi}{12}t)\,dt =\frac{1}{12}
 </math>