6.5 Average Value of a Function/1: Difference between revisions

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f(x) = 4x-x^2, (0, 4)
f(x) = 4x-x^2, (0, 4)
</math>
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<math>
\begin{align}

Revision as of 23:00, 28 November 2022

Find the average value of the function on the given interval.

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