5.5 The Substitution Rule/61: Difference between revisions
No edit summary |
No edit summary |
||
| Line 2: | Line 2: | ||
= <math>\int_{0}^{13}\frac{1}{2^3\sqrt{t^2}}dt</math> | = <math>\int_{0}^{13}\frac{1}{2^3\sqrt{t^2}}dt</math> | ||
= <math>\frac{1}{2}\int_{0}^{13}\frac{1}{\sqrt[3]{t^2}}dt</math> | = <math>\frac{1}{2}\int_{0}^{13}\frac{1}{\sqrt[3]{t^2}}dt</math> | ||
= <math>\frac{1}{2}\int_{0}^{13}\frac{1}{t^\frac{2}{3}}dt</math> | |||
Revision as of 19:24, 20 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^{13}\frac{dx}{\sqrt[3]{(1+2x)^2}}} = Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{0}^{13}\frac{1}{2^3\sqrt{t^2}}dt} = Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \frac{1}{2}\int_{0}^{13}\frac{1}{\sqrt[3]{t^2}}dt} = Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \frac{1}{2}\int_{0}^{13}\frac{1}{t^\frac{2}{3}}dt}