5.5 The Substitution Rule/37: Difference between revisions
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&= \int \frac{1}{{u}}(du) | &= \int \frac{1}{{u}}(du) \\[2ex] | ||
<math>\text{Note: } \int \frac{1}{{x}}dx=\ln(x)+C</math> | |||
&= \frac{1}{3}\frac{u^{\frac{1}{2}}}{\frac{1}{2}} + C \\[2ex] | &= \frac{1}{3}\frac{u^{\frac{1}{2}}}{\frac{1}{2}} + C \\[2ex] | ||
&= \frac{2}{3}(3ax+bx^3)^{1/2} + C \\[2ex] | &= \frac{2}{3}(3ax+bx^3)^{1/2} + C \\[2ex] | ||
Revision as of 19:05, 20 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int \cot(x)dx = \int \frac{\cos(x)}{\sin(x)}dx }
![{\displaystyle {\begin{aligned}u&=\sin(x)\\[2ex]du&=\cos(x)\;dx\\[2ex]\end{aligned}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/d86146c5ab9052b4f1c419e803482f36424c663c)
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \int \frac{\cos(x)}{\sin(x)}dx &= \int \frac{1}{\sin(x)}\cos(x)\;dx = \int \frac{1}{\sin(x)}(\cos(x)\;dx) \\[2ex] &= \int \frac{1}{{u}}(du) \\[2ex] <math>\text{Note: } \int \frac{1}{{x}}dx=\ln(x)+C}
&= \frac{1}{3}\frac{u^{\frac{1}{2}}}{\frac{1}{2}} + C \\[2ex]
&= \frac{2}{3}(3ax+bx^3)^{1/2} + C \\[2ex]
&= \frac{2}{3}{\sqrt{3ax+bx^3}} + C
\end{align} </math>