5.4 Indefinite Integrals and the Net Change Theorem/3: Difference between revisions

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\begin{align}
\begin{align}


\int\cos^{3}xdx = \sin{x}-\frac{1}{3}\sin^{3}x+C &= \frac{d}{dx} {[\sin{x} - \frac{1}{3} \sin^3{x} +C]} \\[2ex]
\int\cos^{3}xdx = \sin{x}-\frac{1}{3}\sin^{3}x+C \\[2ex]
 
\frac{d}{dx} {[\sin{x} - \frac{1}{3} \sin^3{x} +C]} \\[2ex]


& ={\cos{x} - \frac{1}{3}\cdot 3\sin^2{x} \cos{x} +0} \\[2ex]
& ={\cos{x} - \frac{1}{3}\cdot 3\sin^2{x} \cos{x} +0} \\[2ex]

Revision as of 17:14, 13 September 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\int \cos ^{3}xdx=\sin {x}-{\frac {1}{3}}\sin ^{3}x+C\\[2ex]{\frac {d}{dx}}{[\sin {x}-{\frac {1}{3}}\sin ^{3}{x}+C]}\\[2ex]&={\cos {x}-{\frac {1}{3}}\cdot 3\sin ^{2}{x}\cos {x}+0}\\[2ex]&=\cos {x}-\sin ^{2}{x}\cos {x}\\[2ex]&=\cos {x}-(1-cos^{2}(x))\cos {x}\\[2ex]&=\cos ^{3}{x}\end{aligned}}}


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