5.5 The Substitution Rule/51: Difference between revisions
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\begin{align} | \begin{align} | ||
\int {u^{25}} du = \frac{1}{26}{u^{26}} \\[2ex] | |||
&= \cfrac{(x-1)^{26}} {26}\bigg|_{0}^{2} \\[2ex] | &= \cfrac{(x-1)^{26}} {26}\bigg|_{0}^{2} \\[2ex] | ||
Revision as of 17:25, 7 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \int_{0}^{2} ({x-1})^{25} dx \\[2ex] \end{align} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} u &= x-1 \\[2ex] du &= dx \\[2ex] \end{align} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \int {u^{25}} du = \frac{1}{26}{u^{26}} \\[2ex] &= \cfrac{(x-1)^{26}} {26}\bigg|_{0}^{2} \\[2ex] &= \cfrac{(2-1)^{26}} {26} - \cfrac {(0-1)^{26}} {26} \\[2ex] &= 0 \end{align} }