5.5 The Substitution Rule/7: Difference between revisions
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\int\{xsin{(x^{2})}dx &=\frac{1}{2}\int\sin{u}du \\[2ex] | \int\{xsin{(x^{2})}dx &=\frac{1}{2}\int\sin{u}du \\[2ex] | ||
&= -\frac{1}{2}cos{u}+C &=-\frac{1}{2}cos{x^{2}}+C | &= -\frac{1}{2}cos{u}+C&=-\frac{1}{2}cos{x^{2}}+C | ||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 16:55, 7 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int\{xsin{(x^{2})}dx }
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}u&=x^{2}\\[2ex]du&=2xdx\\[2ex]{\frac {1}{2}}du&=dx\\[2ex]\end{aligned}}}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} \int\{xsin{(x^{2})}dx &=\frac{1}{2}\int\sin{u}du \\[2ex] &= -\frac{1}{2}cos{u}+C&=-\frac{1}{2}cos{x^{2}}+C \end{align} }