5.3 The Fundamental Theorem of Calculus/33: Difference between revisions
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<math>\int_{1}^{2}\left(1+2y | <math>\int_{1}^{2}\left(1+2y\right)^2dy | ||
=\int_{1}^{2}\left(4y^2+4y+1\right)dy | =\int_{1}^{2}\left(4y^2+4y+1\right)dy | ||
=1y+\frac{4y^3}{3}+\frac{4y^2}{2}\bigg|_{1}^{2} | =1y+\frac{4y^3}{3}+\frac{4y^2}{2}\bigg|_{1}^{2} | ||
=2+\frac{32}{3}+\frac{16}{2}-\left(1+\frac{4}{3}+\frac{4}{2}\right) | =2+\frac{32}{3}+\frac{16}{2}-\left(1+\frac{4}{3}+\frac{4}{2}\right) | ||
=\frac{49}{3}</math> | =\frac{49}{3}</math> | ||
Revision as of 21:27, 6 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int_{1}^{2}\left(1+2y\right)^2dy =\int_{1}^{2}\left(4y^2+4y+1\right)dy =1y+\frac{4y^3}{3}+\frac{4y^2}{2}\bigg|_{1}^{2} =2+\frac{32}{3}+\frac{16}{2}-\left(1+\frac{4}{3}+\frac{4}{2}\right) =\frac{49}{3}}