5.5 The Substitution Rule/25: Difference between revisions

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<math>
<math>
\sqrt{u}du=\frac{2u^\frac{2}{3}}{3}+C
\sqrt{u}du=\frac{2u^{2/3}}{3}+C
</math>
</math>


<math>
<math>
=\frac{2}{3}(e^x+1)^\frac{3}{2}
=\frac{2}{3}(e^x+1)^{3/2}
</math>
</math>

Latest revision as of 19:10, 2 September 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int e^x\sqrt{1+e^x}dx }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle u=1+e^x }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle du=e^xdx }


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int e^x\sqrt{1+e^x}dx=\int\sqrt{u}du }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \sqrt{u}du=\frac{2u^{2/3}}{3}+C }

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle =\frac{2}{3}(e^x+1)^{3/2} }