5.5 The Substitution Rule/21: Difference between revisions

From Mr. V Wiki Math
Jump to navigation Jump to search
No edit summary
No edit summary
Line 1: Line 1:
<math>
<math>
\int \frac{\cos{(\sqrt{t})}}{\sqrt{t}} dt
\int \frac{\cos{(\sqrt{t})}}{\sqrt{t}} dt
</math>
<math>
\begin{align}
& \int\frac{\left(\ln(x)\right)^2}{x}dx \ = \ \int u^2du \\[2ex]
& = \ \frac{u^{2+1}}{2+1}du \ = \ \frac{1}{3}u^3+C \\[2ex]
& u=\ln(x) \\
& du=\frac{1}{x}dx \\
& = \ \frac{1}{3}(\ln(x))^3+C
\end{align}
</math>
</math>

Revision as of 08:23, 7 September 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int \frac{\cos{(\sqrt{t})}}{\sqrt{t}} dt }


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \int\frac{\left(\ln(x)\right)^2}{x}dx \ = \ \int u^2du \\[2ex] & = \ \frac{u^{2+1}}{2+1}du \ = \ \frac{1}{3}u^3+C \\[2ex] & u=\ln(x) \\ & du=\frac{1}{x}dx \\ & = \ \frac{1}{3}(\ln(x))^3+C \end{align} }