5.5 The Substitution Rule/1: Difference between revisions
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& u=-x \\ [2ex] | & u=-x \\ [2ex] | ||
& du=- | & du=-dx\\ [2ex] | ||
\end{align} | \end{align} | ||
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<math> | <math> | ||
-\int{e^{u}} du = -e^{u} = -e^{-x}+C | \int{e^{-x}} dx = -\int{e^{u}} du = -e^{u} = -e^{-x}+C | ||
</math> | </math> | ||
Revision as of 19:54, 1 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \int{e^{-x}} dx, \quad u=-x \\[2ex] & u=-x \\ [2ex] & du=-dx\\ [2ex] \end{align} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int{e^{-x}} dx = -\int{e^{u}} du = -e^{u} = -e^{-x}+C }