5.5 The Substitution Rule/1: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 4: | Line 4: | ||
& \int{e^{-x}} dx , u=-x \\[2ex] &= | & \int{e^{-x}} dx , u=-x \\[2ex] &= | ||
& | & u=-x \\ [2ex] | ||
& | & du=-dx\\ [2ex] | ||
&= \int{e^{-x}} dx \\ [2ex] | &= \int{e^{-x}} dx \\ [2ex] | ||
Revision as of 19:43, 1 September 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&\int {e^{-x}}dx,u=-x\\[2ex]&=&u=-x\\[2ex]&du=-dx\\[2ex]&=\int {e^{-x}}dx\\[2ex]&=-\int {e^{u}}du\\[2ex]&=-e^{u}du\\[2ex]&=-e^{-x}+C\\[2ex]\end{aligned}}}