5.5 The Substitution Rule/1: Difference between revisions
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& du=-dx\\ [2ex] | & du=-dx\\ [2ex] | ||
& \int{e^{-x}} dx = | & \int{e^{-x}} dx = &= -\int{e^{u}} du = &= -e^{u} du = &= -e^{-x}+C | ||
&= -\int{e^{u}} du = | |||
&= -e^{u} du = | |||
&= -e^{-x}+C | |||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 19:36, 1 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \int{e^{-x}} dx , u=-x \\[2ex] & u=-x \\ [2ex] & du=-dx\\ [2ex] & \int{e^{-x}} dx = &= -\int{e^{u}} du = &= -e^{u} du = &= -e^{-x}+C \end{align} }