6.2 Trigonometric Functions: Unit Circle Approach/15: Difference between revisions

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\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac\5 sqrt{21}{21}\\[2ex]
\sin{(t)} &= \frac\sqrt{21}{5} & \csc{(t)} &= \frac{2\sqrt{21}}{21}
\cos{(t)} &= -\frac{2}{5} & \sec{(t)} &= \frac{r}{x}\\[2ex]  
  \cos{(t)} &= -\frac{2}{5} & \sec{(t)} &= \frac{r}{x}\\[2ex]  
\tan{(t)} &= -\frac\sqrt{21}{2} & \cot{(t)} &= \frac{x}{y} \\[2ex]
\tan{(t)} &= -\frac\sqrt{21}{2} & \cot{(t)} &= \frac{x}{y} \\[2ex]



Revision as of 19:20, 30 August 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}-{\frac {2}{5}},{\frac {\sqrt {21}}{5}}\sin {(t)}&={\frac {\sqrt {21}}{5}}&\csc {(t)}&={\frac {2{\sqrt {21}}}{21}}\cos {(t)}&=-{\frac {2}{5}}&\sec {(t)}&={\frac {r}{x}}\\[2ex]\tan {(t)}&=-{\frac {\sqrt {21}}{2}}&\cot {(t)}&={\frac {x}{y}}\\[2ex]\end{aligned}}}


\end{align} </math>