6.1 Areas Between Curves/18: Difference between revisions
No edit summary |
No edit summary |
||
| Line 28: | Line 28: | ||
\int_{-2}^{2} \left((8-x^2) - (x^2)\right)dx &= \int_{-2}^{2}\left(8-2x^2\right)dx \\[2ex] | \int_{-2}^{2} \left((8-x^2) - (x^2)\right)dx &= \int_{-2}^{2}\left(8-2x^2\right)dx \\[2ex] | ||
&= \left(8x-\frac{2x^3}{3}\right)\bigg|_{-2}^{2} \\[2ex] | &= \left(8x-\frac{2x^3}{3}\right)\bigg|_{-2}^{2} \\[2ex] | ||
&= \left(8(2)-\frac{2(2)^3}{3}\right) - \left(8(-2)-\frac{2(-2)^3}{3}\right) | &= \left(8(2)-\frac{2(2)^3}{3}\right) - \left(8(-2)-\frac{2(-2)^3}{3}\right) = \left(16-\frac{16}{3}\right)-\left(-16+\frac{16}{3}\right) | ||
\end{align} | \end{align} | ||
</math> | </math> | ||
Revision as of 20:47, 26 August 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} & \color{red}\mathbf{y=8-x^2} & \color{royalblue}\mathbf{y=x^2} \\ & x=-3 & x=3 \\ \end{align} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} 8-x^2 &= x^2 \\ 8 &= 2x^2 \\ 4 &= x^2 \\ \end{align} }
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle x=\pm2}
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\int _{-2}^{2}\left((8-x^{2})-(x^{2})\right)dx&=\int _{-2}^{2}\left(8-2x^{2}\right)dx\\[2ex]&=\left(8x-{\frac {2x^{3}}{3}}\right){\bigg |}_{-2}^{2}\\[2ex]&=\left(8(2)-{\frac {2(2)^{3}}{3}}\right)-\left(8(-2)-{\frac {2(-2)^{3}}{3}}\right)=\left(16-{\frac {16}{3}}\right)-\left(-16+{\frac {16}{3}}\right)\end{aligned}}}