5.3 The Fundamental Theorem of Calculus/23: Difference between revisions
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&\int_{0}^{1}x^\ | &\int_{0}^{1}x^{\frac{4}{5}}dx \\[2ex] | ||
Revision as of 20:41, 6 September 2022
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} &\int_{0}^{1}x^{\frac{4}{5}}dx \\[2ex] &\cfrac{5\cdot \sqrt[5]{x^4}}{9}\bigg|_{0}^{1} \\[2ex] &\cfrac{5\cdot \sqrt{1^4}}{9}-\cfrac{5 \sqrt[5]{0^4}}{9} \\[2ex] &=\cfrac{5}{9} \end{align} }