5.3 The Fundamental Theorem of Calculus/35: Difference between revisions
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\begin{align} | \begin{align} | ||
\int_{1}^{9}\frac{1}{2x}dx = \frac{1}{2}\int_{1}^{9}\frac{1}{x}dx = \frac{1}{2}\ln{|x|}\bigg|_{1}^{9} | \int_{1}^{9}\frac{1}{2x}dx = \frac{1}{2}\int_{1}^{9}\frac{1}{x}dx = | ||
\frac{1}{2}\ln{|x|}\bigg|_{1}^{9} = \frac{1}{2}\ln{|9|}-frac{1}{2}\ln{|1|}= | |||
\ln{|9|} | |||
\end {align} | \end {align} | ||
</math> | </math> | ||
Revision as of 19:25, 25 August 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\int _{1}^{9}{\frac {1}{2x}}dx={\frac {1}{2}}\int _{1}^{9}{\frac {1}{x}}dx={\frac {1}{2}}\ln {|x|}{\bigg |}_{1}^{9}={\frac {1}{2}}\ln {|9|}-frac{1}{2}\ln {|1|}=\ln {|9|}\end{aligned}}}