5.3 The Fundamental Theorem of Calculus/23: Difference between revisions

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&= \cfrac{5 \sqrt[5]{x^4}}{9} \\[2ex]
&= \cfrac{5 \sqrt[5]{x^4}}{9} \\[2ex]


&= \cfrac{5 \sqrt[5]{x^4}}{9}\bigg|_{0}^{1}
&= \cfrac{5 \sqrt[5]{x^4}}{9}\bigg|_{0}^{1} \\[2ex]
 
&=




\end{align}
\end{align}
</math>
</math>

Revision as of 19:07, 25 August 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&\int _{0}^{1}x^{\cfrac {4}{5}}dx\\[2ex]&={\cfrac {5{\sqrt[{5}]{x^{4}}}}{9}}\\[2ex]&={\cfrac {5{\sqrt[{5}]{x^{4}}}}{9}}{\bigg |}_{0}^{1}\\[2ex]&=\end{aligned}}}