5.5 The Substitution Rule/33: Difference between revisions

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Line 7: Line 7:
\begin{align}
\begin{align}
u &= \cot{(x)} \\[2ex]
u &= \cot{(x)} \\[2ex]
du &= csc^2{(x)}dx \\[2ex]
du &= -csc^2{(x)}dx \\[2ex]
-du &= \csc^2{(x)}dx \\[2ex]
-du &= \csc^2{(x)}dx \\[2ex]
\end{align}
\end{align}

Latest revision as of 09:25, 16 December 2022

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \int {\sqrt{\cot(x)}} \csc^2{(x)}dx }


Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} u &= \cot{(x)} \\[2ex] du &= -csc^2{(x)}dx \\[2ex] -du &= \csc^2{(x)}dx \\[2ex] \end{align} }


Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}&=-\int {({\sqrt {u}})}du\\[2ex]&=\int (u^{\frac {1}{2}})du\\[2ex]&=-{\frac {2}{3}}u+C\\[2ex]&=-{\frac {2}{3}}(\cot {(x)})^{\frac {3}{2}}+C\end{aligned}}}