6.2 Volumes/15: Difference between revisions

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<math>
<math>
\begin{align}
\begin{align}
\pi\int_-1^1\left(1-y^2\right)^2 dy & = \pi\int_-1^1\left(1-2y^2+y^4\right)dy \\[2ex]
\pi\int_{-1}^{1}\left(1-y^2\right)^{2} dy & = \pi\int_{-1}^{1}\left(1-2y^2+y^4\right)dy \\[2ex]


&= \pi\left[y-\frac{2}{3}y^3+\frac{y^5}{5}\right]\Bigg|_-1^1 \\[2ex]
&= \pi\left[y-\frac{2}{3}y^3+\frac{y^5}{5}\right]\Bigg|_{-1}^{1} \\[2ex]
&= \pi\left[1+\frac{2}{3}+\frac{1}{5}\right]- \pi\left[-1+\frac{2}{5}-\frac{1}{5}\right] \\[2ex]
&= \pi\left[1+\frac{2}{3}+\frac{1}{5}\right]- \pi\left[-1+\frac{2}{5}-\frac{1}{5}\right] \\[2ex]
&= \frac{16\pi}{15}
&= \frac{16\pi}{15}

Latest revision as of 17:14, 13 December 2022

Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\begin{aligned}\pi \int _{-1}^{1}\left(1-y^{2}\right)^{2}dy&=\pi \int _{-1}^{1}\left(1-2y^{2}+y^{4}\right)dy\\[2ex]&=\pi \left[y-{\frac {2}{3}}y^{3}+{\frac {y^{5}}{5}}\right]{\Bigg |}_{-1}^{1}\\[2ex]&=\pi \left[1+{\frac {2}{3}}+{\frac {1}{5}}\right]-\pi \left[-1+{\frac {2}{5}}-{\frac {1}{5}}\right]\\[2ex]&={\frac {16\pi }{15}}\end{aligned}}}