7.1 Integration By Parts/53: Difference between revisions

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<math>y= xe^{-0.4x} ~~~ x=0,x=1</math>
<math>y= xe^{-0.4x} ~~~ y=0,x=5</math>


<math> \underbrace{\int_{0}^{5}xe^{-0.4x}dx} </math>  
<math>
 
\begin{align}
 
\underbrace{\int_{0}^{5}xe^{-0.4x}dx}_{
 
\begin{aligned}
 
u &= x & dv &= e^{-0.4x} dx \\[0.6ex]
du &= dx & v &= \frac{5}{2}e^{-0.4x}
\end{aligned}} \\ [2ex]
 
\end{align}
 
</math>
 
 
<math>
\left [ \frac{5}{2}e^{-0.4x} \right ]_{0}^{5}+\int_{0}^{5}\frac{5}{2}e^{-0.4x}dx
</math>


<math>
<math>
\begin{align}
\begin{align}
u &= x \quad dv= e^{-0.4x} dx \\[2ex]
u &= -0.4x
du &= 2xdx        \qquad v= -e^{-x} \\[2ex]
  \\[2ex]
du &= -0.4dx \\[2ex]


\end{align}
\end{align}
</math>
<math>
\left (-\frac{25}{2}e^{-2}-0  \right )+\frac{25}{4}\int_{0}^{5}e^{u}
</math>
<math>
-\frac{25}{2}e^{-2}+\left [ \frac{25}{4}\left ( e^{-0.4x} \right ) \right ]~~~=~~~ -\frac{25}{2}e^{-2}-\frac{25}{4}e^{-2}+\frac{25}{4}~~~=~~~
-\frac{75}{4}e^{-2}+ \frac{25}{4}
</math>
</math>

Latest revision as of 16:48, 13 December 2022