6.1 Areas Between Curves/21: Difference between revisions

From Mr. V Wiki Math
Jump to navigation Jump to search
No edit summary
No edit summary
 
(One intermediate revision by the same user not shown)
Line 6: Line 6:
&=\int_{1}^{-1}[2-2y^2]dy=[2y-2(\frac{y^3}{3})|_{-1}^{0}\\[2ex]
&=\int_{1}^{-1}[2-2y^2]dy=[2y-2(\frac{y^3}{3})|_{-1}^{0}\\[2ex]
&=2(1)-2(\frac{(1)^3}{3})-[2(-1)-2(\frac{(-1)^3}{3})]\\[2ex]
&=2(1)-2(\frac{(1)^3}{3})-[2(-1)-2(\frac{(-1)^3}{3})]\\[2ex]
&=2-\frac{2}{3}+2-\frac{2}{3}=4-\frac{4}{3}\\[2ex]
&=2-\frac{2}{3}+2-\frac{2}{3}\\[2ex]
&=\frac{8}{3}
&=\frac{8}{3}
\end{align}
\end{align}
<\math>
</math>

Latest revision as of 19:51, 22 September 2022

6.1number21.png

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \begin{align} x&=1-y^2, x=y^2-1 \\[1ex] A &= \int_{a}^{b}[x_R-x_L]dy=\int_{1}^{-1}[(1-y^2)-(y^2-1)]dy\\[2ex] &=\int_{1}^{-1}[2-2y^2]dy=[2y-2(\frac{y^3}{3})|_{-1}^{0}\\[2ex] &=2(1)-2(\frac{(1)^3}{3})-[2(-1)-2(\frac{(-1)^3}{3})]\\[2ex] &=2-\frac{2}{3}+2-\frac{2}{3}\\[2ex] &=\frac{8}{3} \end{align} }