5.3 The Fundamental Theorem of Calculus/21: Difference between revisions
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<math> | <math> | ||
\int_{1}^{4}(5-2t+3t^2)\,dt=5t-t^2+t^3\bigg|_{1}^{4}=\left[5(4)-(4)^2+(4)^3\right]- | \int_{1}^{4}(5-2t+3t^2)\,dt=5t-t^2+t^3\bigg|_{1}^{4}=\left[5(4)-(4)^2+(4)^3\right]-\left[5(1)-(1)^2+(1)^3\right]=63 | ||
</math> | </math> | ||
Latest revision as of 20:40, 6 September 2022
Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \int _{1}^{4}(5-2t+3t^{2})\,dt=5t-t^{2}+t^{3}{\bigg |}_{1}^{4}=\left[5(4)-(4)^{2}+(4)^{3}\right]-\left[5(1)-(1)^{2}+(1)^{3}\right]=63}