5.3 The Fundamental Theorem of Calculus/17: Difference between revisions
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<math>y=\int\limits_{1-3x}^{1}\frac{1}{(1+u^2)}x^3, dx</math> | <math>y=\int\limits_{1-3x}^{1}\frac{1}{(1+u^2)}x^3, dx</math> | ||
= | = | ||
<math>(0)*f(1)-(-3)*f(1-3x)</math> | <math>(0)*f(1)-(-3)*f(1-3x)</math> | ||
Revision as of 01:31, 24 August 2022
FTC #1 Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle y=\int\limits_{1-3x}^{1}\frac{x^3}{(1+u^2)} dx}
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle G(x)=f(x)}
so Failed to parse (Conversion error. Server ("https://en.wikipedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle y=\int \limits _{1-3x}^{1}{\frac {1}{(1+u^{2})}}x^{3},dx}
= Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle (0)*f(1)-(-3)*f(1-3x)}