Freddy: Difference between revisions

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<math>\forall x \in X, \quad \exists y \leq \epsilon
<math>\forall x \in X, \quad \exists y \leq \epsilon
</math>
</math>
$\displaystyle{{a}_{n}}=\frac{5^{2n}}{{{4}^{3n}}}$

Revision as of 15:47, 16 June 2023

Hi my name is Freddy





$\displaystyle{{a}_{n}}=\frac{5^{2n}}{{{4}^{3n}}}$