Jeremy: Difference between revisions

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<Math>g(x)=\sqrt[-5]{3x^9-7}</Math><br>
<Math>g(x)=\sqrt[-5]{3x^9-7}</Math><br>
<Math>(f+g)(x)=\sqrt[3]{\frac{4x^3+9y^3_4}{x}}+\sqrt[-5]{3x^9-7}</Math><br>
<Math>(f+g)(x)=\sqrt[3]{\frac{4x^3+9y^3_4}{x}}+\sqrt[-5]{3x^9-7}</Math><br>
<Math>\frac{d}{dx}\cdot\frac{f}{g}=f'/cdot g - g'f

Revision as of 17:20, 28 March 2023

Hallo mein heiße ist Jeremy



<Math>\frac{d}{dx}\cdot\frac{f}{g}=f'/cdot g - g'f