Chris: Difference between revisions
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<math>g(x)= x+2 </math><br> | <math>g(x)= x+2 </math><br> | ||
<math> (f(g)),(f-g),(f+g),({\frac{f}{x}}) </math> | <math> (f(g)),(f-g),(f+g),({\frac{f}{x}}) </math> | ||
<math>{\frac{d}{dx}} [c] = 0 </math> <br> | |||
<math>{\frac{d}{dx}} [c\cdot f(x)] = c\cdot{\frac{d}{dx}} [f(x)] </math> <br> | |||
<math>{\frac{d}{dx}} [f(x)\pm g(x)] = {\frac{d}{dx}} [f(x)] \pm {\frac{d}{dx}} [g(x)] </math> <br> | |||
<math>{\frac{d}{dx}} [c] = 0 </math> <br> | |||
<math>{\frac{d}{dx}} [c] = 0 </math> <br> | |||
Revision as of 17:07, 28 March 2023
Je m'appelle Christopher Sanchez.
![{\displaystyle {\frac {d}{dx}}[c]=0}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/834381b512bc1d1fc47c2d26ce38ae71daaa1053)
![{\displaystyle {\frac {d}{dx}}[c\cdot f(x)]=c\cdot {\frac {d}{dx}}[f(x)]}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/e100ac3ba73695d9c36ad8ada81efba4c2a01129)
![{\displaystyle {\frac {d}{dx}}[f(x)\pm g(x)]={\frac {d}{dx}}[f(x)]\pm {\frac {d}{dx}}[g(x)]}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/27fc302c62ab11c846d1255170f40351d3461dfe)