6.5 Average Value of a Function/5: Difference between revisions
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<math> | <math> | ||
f(t) = te^{-t^2},\quad [0, 5], | f(t) = te^{-t^2},\quad [0, 5], f(t) = \frac{1}{5)} | ||
</math> | </math> | ||
Revision as of 18:32, 16 December 2022
![{\displaystyle f(t)=te^{-t^{2}},\quad [0,5],f(t)={\frac {1}{5)}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/7795be2939b08dba61d23939fda9fa4033589ac0)