6.2 Volumes/9: Difference between revisions

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<math>y^{2}=x, x=2y</math>
<math>
<math>\int_{0}^{2}\pi x=2y-x=y^2</math>
y^{2}=x, x=2y
</math>
 
<math>
\begin{align}
\int_{0}^{4}\pi [2y-y^2]dx &= \pi[2(4)-(4)^{2}] \\[2ex]
&= \pi[8-16] \\[2ex]
&= \frac{64\pi}{15}
\end{align}
</math>

Latest revision as of 02:11, 16 December 2022