6.2 Volumes/9: Difference between revisions

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<math>y^{2}=x, x=2y
<math>y^{2}=x, x=2y</math>
\begin{align}
\begin{align}
\int_{0}^{4}\pi [2y-y^2]dx \\[2ex]
\int_{0}^{4}\pi [2y-y^2]dx \\[2ex]

Revision as of 02:02, 16 December 2022

\begin{align} \int_{0}^{4}\pi [2y-y^2]dx \\[2ex] &= \pi[2(4)-(4)^{2} \end{align} </math>