6.2 Volumes/9: Difference between revisions

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<math>y^{2}=x, x=2y
<math>y^{2}=x, x=2y
\begin{align}
\begin{align}
&= \int_{0}^{2}\pi [x=2y-x=y^2] \\[2ex]
\int_{0}^{4}\pi [2y-y^2]dx \\[2ex]
&= \pi[2(4)-(4)^{2}
\end{align}
\end{align}
</math>
</math>
<math>


<math>=\frac{64pi}{15}</math>
<math>=\frac{64pi}{15}</math>

Revision as of 02:02, 16 December 2022