6.2 Volumes/9: Difference between revisions

Revision as of 01:33, 16 December 2022

$y^{2}=x,x=2y$ $\int _{0}^{2}\pi (x=2y-x=y^{2})=64pi/15$

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 <math>y^{2}=x, x=2y</math>
-<math>\int_{0}^{2}\pi (x=2y-x=y^2)</math>
+<math>\int_{0}^{2}\pi (x=2y-x=y^2)
+=64pi/15</math>